function display_db_error($msg, $sql_statement=null, $exit=true)
{
- global $db, $debug;
+ global $db, $debug, $go_debug;
$warning = $msg==null;
$db_error = db_error_no();
if ($debug == 1)
{
$str .= "sql that failed was : " . $sql_statement . "<br>";
+ if ($go_debug > 1) display_backtrace();
}
$str .= "<br><br>";